Asked by John
A mixture of Xe, Kr, and Ar has a total pressure of 6.7 atm. What is the mole fraction of Kr if the partial pressures of XE and Ar are 1.6 atm and 2.8 atm?
Did anyone get .343 ?
Did anyone get .343 ?
Answers
Answered by
bobpursley
partial pressure is directly related to mole fraction.
partial pressure of Kr = 6.7-1.6-2.8
molefractionKr=partialpressureKr/6.7atm
partial pressure of Kr = 6.7-1.6-2.8
molefractionKr=partialpressureKr/6.7atm
Answered by
John
Thats what I did! THANK YOU!
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