Asked by Sarah
Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH2) with 0.180 M HCl. The Kb of methylamine is 5.0× 10^–4.
Answers
Answered by
DrBob222
At the equivalence point we have the salt, CH3NH3Cl and it will hydrolyze to give you an acidic solution. (salt) at the equivalence point is 0.09M.
.........CH3NH3^+ + H2O == H3O^+ + CH3NH2
I.........0.09..............0........0
C...........-x..............x........x
E.......0.09-x..............x........x
Kb = (CH3NH2)(H3O^+)/((CH3NH3^+)
Substitute and solve for x = (H3O^+) and convert to pH.
.........CH3NH3^+ + H2O == H3O^+ + CH3NH2
I.........0.09..............0........0
C...........-x..............x........x
E.......0.09-x..............x........x
Kb = (CH3NH2)(H3O^+)/((CH3NH3^+)
Substitute and solve for x = (H3O^+) and convert to pH.
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