Asked by Brianna
A 20.0-kg model plane flies horizontally at a constant speed of 12.2 m/s.
(a) Calculate its kinetic energy.
. J
(b) The plane goes into a dive and levels off 20.0 m closer to Earth. How much potential energy does it lose during the dive? Assume no additional drag.
J
(c) How much kinetic energy does the plane gain during the dive?
J
(d) What is its new kinetic energy?
J
(e) What is its new horizontal velocity?
m/s
-i got at 1488.4
(a) Calculate its kinetic energy.
. J
(b) The plane goes into a dive and levels off 20.0 m closer to Earth. How much potential energy does it lose during the dive? Assume no additional drag.
J
(c) How much kinetic energy does the plane gain during the dive?
J
(d) What is its new kinetic energy?
J
(e) What is its new horizontal velocity?
m/s
-i got at 1488.4
Answers
Answered by
Elena
KE =m•v²/2 =20•12.2²/2 =1488 J.
ΔPE = m•g•Δh = 20•9.8•20 = 3920 J.
Δ KE = ΔPE = 3920 J.
KE1 =KE + Δ KE = 1488 +3920= 5408 J.
The horizontal velocity isn’t changed. The vertical component is appeared, therefore, the velocity (as the vector sum of horizontal and vertical components) is increased.
ΔPE = m•g•Δh = 20•9.8•20 = 3920 J.
Δ KE = ΔPE = 3920 J.
KE1 =KE + Δ KE = 1488 +3920= 5408 J.
The horizontal velocity isn’t changed. The vertical component is appeared, therefore, the velocity (as the vector sum of horizontal and vertical components) is increased.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.