A 2.5kg ball strikes a wall with a velocity of 8.5m/s to the left. The ball bounces off the wall with a velocity of 7.5m/s to the right. If the ball is in contact with the wall for .25s, what is the constant force exerted on the ball by the wall?

Answer 1

calculate change in the momentum. remember that after it experiences this "perfectly elastic collision" it has a negative velocity. Therefore the change in momentum would be p = abs|m1v1 + m2v2|
change in momentum p = Ft
Force would be the average force or in this case the constant force