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A bullet of mass 35g strikes a stationary wooden block of mass 2.6kg, becomes embedded in the block, and they both move off at 7.5m/s. What was the original velocity of the bullet?

2 answers

m1 = 35 g = 0.035 kg, v1 =?
m2 = 2.6 kg, v2 =0,
u = 7.5 m/s
m1•v1 =(m1+m2) •u,
v1 =(m1+m2) •u/m1 = ......

564'64m/s

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