Question

Approximate the sum of the series correct to four decimal places.
n=1 to infinity
(-1)^n/4^n*n!

Answer 1

The answer I got was 0.9336. I did

Answer 2

(-1)^1/4^1*1 + (-1)^2/4^2*2 + (-1)^3/4^3*3 + (-1)^4/4^4*4 + (-1)^5/4^5*5 + (-1)^6/4^6*6