Asked by ouii
A light beam ( 557.1 nm) illustrates a single slit 0.85mm wide. (a) How far is the screen from the slit if there is 0.85 mm between the first minimum and the central minimum on the screen? (b) what is the width of the central maximum on the screen?
Answers
Answered by
Elena
(a) b•sinφ = k•λ,
sinφ = k•λ/b = 1•557.1•10^9/0.85•10^-3 =
= 6.56•10^-4 = tan φ
tan φ = x/L ,
L = 0.85•10^-3/6.56•10^-4 = 1.3 m.
(b) 2•0.85 mm = 1.7 mm
sinφ = k•λ/b = 1•557.1•10^9/0.85•10^-3 =
= 6.56•10^-4 = tan φ
tan φ = x/L ,
L = 0.85•10^-3/6.56•10^-4 = 1.3 m.
(b) 2•0.85 mm = 1.7 mm
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.