Asked by julie
A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 25.0° and the angle of refraction is 14.0°, find the critical angle for the liquid when surrounded by air.
im not sure how to start this problem.
im not sure how to start this problem.
Answers
Answered by
julie
just kidding i figured it out.
Answered by
bobpursley
first, find the index of refraction
n= sin25/sin14
then, critical angle= arcsin(1/n)=arcsin(sin14/sin25) about 35 degrees, work it out and check me.
n= sin25/sin14
then, critical angle= arcsin(1/n)=arcsin(sin14/sin25) about 35 degrees, work it out and check me.
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