Asked by Kaelan
Hey guys I need help understanding this problem. If you can list why/reasoning for each step of the answer I would appreciate it greatly!
Interpret the given equation in terms of relatinve numbers of representative particles, number of moles, and masses of reactants and products.
2K(s)+2H2O(l)-->2KOH(Aq)+H2(g)
Interpret the given equation in terms of relatinve numbers of representative particles, number of moles, and masses of reactants and products.
2K(s)+2H2O(l)-->2KOH(Aq)+H2(g)
Answers
Answered by
DrBob222
It look straight forward to me. I'll do one of them.
2 mols K + 2 mols H2O yield 2 mols KOH and 1 mol H2.
Now you can do the masses.
2*atomic mass K = 78 g K combine with 2*18 or 36 g H2O etc.
2 mols K + 2 mols H2O yield 2 mols KOH and 1 mol H2.
Now you can do the masses.
2*atomic mass K = 78 g K combine with 2*18 or 36 g H2O etc.
Answered by
Angel
how many grams of solute is in 64.3 mL of 0.0238 molarity KOH?
Answered by
DrBob222
mols = M x L. You know M and L, solve for mols.
Then mol = grams/molar mass.
You know mols and molar mass, solve for grams.
Then mol = grams/molar mass.
You know mols and molar mass, solve for grams.
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