Asked by Vinny
Hey, guys, I need really need some help and I would appreciate your help thank you.
21-25 Which of these equations are redox reactions?
21. _____ C4H8(g) + _____ O2(g) → _____ CO2(g) + _____ H2O(g)
22. _____ C4H10(g) + _____ O2(g) → _____ CO2(g) + _____ H2O(g)
23. _____ KMnO4(s) → _____ K2MnO4(s) + _____ MnO2(s) +_____O2(g)
24. ____ AgNO3(aq) + ____ Zn(s) → ____ Zn(NO3)2(aq) + ____ Ag(s)
25. ____ Na3PO4(aq) + ____ AlCl3(aq) → ____ AlPO4(s) + ____ NaCl(aq)
21-25 Which of these equations are redox reactions?
21. _____ C4H8(g) + _____ O2(g) → _____ CO2(g) + _____ H2O(g)
22. _____ C4H10(g) + _____ O2(g) → _____ CO2(g) + _____ H2O(g)
23. _____ KMnO4(s) → _____ K2MnO4(s) + _____ MnO2(s) +_____O2(g)
24. ____ AgNO3(aq) + ____ Zn(s) → ____ Zn(NO3)2(aq) + ____ Ag(s)
25. ____ Na3PO4(aq) + ____ AlCl3(aq) → ____ AlPO4(s) + ____ NaCl(aq)
Answers
Answered by
DrBob222
All but 25 are redox equations. What is it you don't understand about this. If the oxidation state changes for ANY ONE reactant/product then you have a redox equation.
C4H8(g) + _____ O2(g) → _____ CO2(g) + _____ H2O(g)
<b> I see at first glane that I have O2 on the left, all by itself, but I quickly see on the right that it is a compound. So I know that is a redox. Technically, O changes from zero oxidation state to 2- on the right. (both CO2 and H2O)</b>
22. _____ C4H10(g) + _____ O2(g) → _____ CO2(g) + _____ H2O(g)
<b> Same thing here.</b>
23. _____ KMnO4(s) → _____ K2MnO4(s) + _____ MnO2(s) +_____O2(g)
<b>I see O in KMnO4 on the left but O2 on the right. Same as the above but reversed. I also see MnO4 on the left but MnO2 on the right so I know something changed</b>
24. ____ AgNO3(aq) + ____ Zn(s) → ____ Zn(NO3)2(aq) + ____ Ag(s)
</b>I see Ag on the left in a compound but on the right a metal. Also I see Zn metal on the left but compound on the right. Must be redox.</b>
25. ____ Na3PO4(aq) + ____ AlCl3(aq) → ____ AlPO4(s) + ____ NaCl(aq)
<b>Na, PO4, Al, Cl all stay the same on left and right so not redox.
<i> Also not that you can do it the laborious way and determine the oxidation state of EACH element in an equation and see if anything changed.
C4H8(g) + _____ O2(g) → _____ CO2(g) + _____ H2O(g)
<b> I see at first glane that I have O2 on the left, all by itself, but I quickly see on the right that it is a compound. So I know that is a redox. Technically, O changes from zero oxidation state to 2- on the right. (both CO2 and H2O)</b>
22. _____ C4H10(g) + _____ O2(g) → _____ CO2(g) + _____ H2O(g)
<b> Same thing here.</b>
23. _____ KMnO4(s) → _____ K2MnO4(s) + _____ MnO2(s) +_____O2(g)
<b>I see O in KMnO4 on the left but O2 on the right. Same as the above but reversed. I also see MnO4 on the left but MnO2 on the right so I know something changed</b>
24. ____ AgNO3(aq) + ____ Zn(s) → ____ Zn(NO3)2(aq) + ____ Ag(s)
</b>I see Ag on the left in a compound but on the right a metal. Also I see Zn metal on the left but compound on the right. Must be redox.</b>
25. ____ Na3PO4(aq) + ____ AlCl3(aq) → ____ AlPO4(s) + ____ NaCl(aq)
<b>Na, PO4, Al, Cl all stay the same on left and right so not redox.
<i> Also not that you can do it the laborious way and determine the oxidation state of EACH element in an equation and see if anything changed.
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