Question

hi guys need help with a few questions.

1. Which equation represents the axis of symmetry of the function y = 2x^2+4x-6? A. y= 1 B. x= 1 C. x=3 D x= -3

2. & 3. What are the coordinates of the vertex of the graph of the function -

2. y = -x^2+6x-11 A. (3,-2) B. (3,16) C. (-3,-29) D. (-3,-20)

3. y = -3x^2 -12x + 3 A. (-2,29) B (2,-15) C. (2, -9) D. (-2,15)

Answer 1

recall that for y = ax^2+bx+c the axis and vertex always lie on the line

x = -b/2a

Answer 2

@steve what question r u talking about

Answer 3

Steve's "big hint" applies to all 3 of your questions.
I will use it on #3

comparing:
y = ax^2 + bx + c , and
y = -3x^2 - 12x + 3, ---> a=-3, b=-12, c=3

the x of the vertex is -b/(2a) = -(-12)/-6 = -2
which also means that the axis of symmetry is
x = -2
to get the y of the vertex, plug it in
y = -3(-2)^2 - 12(-2) + 3
= -3(4) + 24 + 3 = 15
So the vertex is (-2,15)

Now, you do the other two.

Answer 4

Okay I’m just gonna do what everyone wants and what I came here to find but couldn’t
Here’s the answers
1.B
2.A
3.D
4.B
5.D
6.B
I got almost nothing on my quick check so that I could see the correct answers and give them to you guys
This is what the quick check says were actually the correct answers do have fun