Asked by ShelbyA
F(x)=1/4 (x+7)^2+7 Looking for the vertex and the max or min for the above..?
And thank you for checking my work, nice to know I get some of it.
And thank you for checking my work, nice to know I get some of it.
Answers
Answered by
visoth
sorry i didn't see that for some reason on your other post lol
k i would rewrite this first equation a bit so it is in vertex form
vertex form is written like this : f(x)=a(x-h)^2 + k
to rewrite it in this form it will look like this
f(x)= a(x-(-7))^2 +7
a = 1/4 k= 7 h=-7
vertex is (h, k) = (-7, 7)
min/,max is always at the vertex so f(x)=7
k i would rewrite this first equation a bit so it is in vertex form
vertex form is written like this : f(x)=a(x-h)^2 + k
to rewrite it in this form it will look like this
f(x)= a(x-(-7))^2 +7
a = 1/4 k= 7 h=-7
vertex is (h, k) = (-7, 7)
min/,max is always at the vertex so f(x)=7
Answered by
visoth
oh by the way since a=1/4 that means a > o meaning graph opens upward and the vertex point f(-7)=7 is a minimum point
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