Asked by Bryan
1.)A sample of oxygen took 55 seconds to travel a certain distance. How long would it take for the same number of moles of nitrogen to travel the same distance.
2.) A sample of hydrogen gas traveled 45m in a given amount of time. An unknown gas traveled 7.6m in the same amount of time. What is the formula mass of the unknown gas?
2.) A sample of hydrogen gas traveled 45m in a given amount of time. An unknown gas traveled 7.6m in the same amount of time. What is the formula mass of the unknown gas?
Answers
Answered by
DrBob222
1.
The amount of sample is not given so let's make up one; say 1 l is convenient.
rate O2 = 1L/55 sec
rate N2 - 1L/x sec
(1/55)/(1/x) = sqrt (M2/M1)
M2 = molar mass N2
M1 - molar mass O2.
The amount of sample is not given so let's make up one; say 1 l is convenient.
rate O2 = 1L/55 sec
rate N2 - 1L/x sec
(1/55)/(1/x) = sqrt (M2/M1)
M2 = molar mass N2
M1 - molar mass O2.
Answered by
bryan
and do i do the same thing for number 2?
Answered by
DrBob222
yes. The difference is that you have both rates given and are solving for molar mass of one of the gases.
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