Asked by ridhi

an object of mass 0.1kg is rotated in a horizontal circle by a string 1m long. the maximum tension in the string before it breaks is 50N.what is its maximum frequency reached?
Answered by Sinmei
0.28s??
Answered by ridhi
no the answer is 1.6 revolutions per second
Answered by Damon
F = m v^2/r
50 = .1 v^2/1
v^2 = 500
v =10 sqrt 5

circumference = 2 pi r = 2 pi

time around circle = 2 pi /10 sqrt 5

frequency = 1/time = (5/pi) sqrt 5

f = 3.55
Answered by ridhi
are you sure we can use length of the string 1m as the radius? and why?
Answered by Damon
Your problem statement says the string is one meter long.
Answered by ridhi
hmmm...ok thanks :)
Answered by Sinmei
Sry, I misunderstand the question. F=3.55
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