Asked by Anonymous
How many amperes would be needed to produce 60 g of magnesium during the electrolysis of molten MgCl2 in 2 hours?
Answers
Answered by
bobpursley
first, you need two electrons per atom.
atoms Mg= moleMg*AvagNumber= figure that out for 60 gMg
Then, each electron has this charge: 1.6E-19 Coulombs= e
amperes*time= number coulmbs
= 2*e*atoms electrons
amperes= above/120sec
atoms Mg= moleMg*AvagNumber= figure that out for 60 gMg
Then, each electron has this charge: 1.6E-19 Coulombs= e
amperes*time= number coulmbs
= 2*e*atoms electrons
amperes= above/120sec
Answered by
Anonymous
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