Asked by amy

What are the co-vertices of the ellipse 3x^2+2y^2=72?
thank you....
Answered by Steve
divide by 72

x^2/24 + y^2/36 = 1

the semi-major axes have lengths √24 and 6

The center is at (0,0), so the candidates are

(±√24,0) and (0,±6)

Now, which of these are the vertices?
Answered by sam
Is it (0,±6)?
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