a farmer moves along the boundary of a square field of side 10 meter in 40 seconds. what will be the magnitude of displacement of the farmer at the end of 2 minutes and 20 seconds from his initial position?

Answer 1

Perimeter of the field = s = 4•10 =40 m.
v = s/t = 40/40 =1 m/s.
s1 = v•t1 = 1•140 = 140 m =3.5•40 m.
A displacement is the shortest distance from the initial to the final position of a point, therefore, it depends on the initial position of the farmer. If he begins to move from the midpoint of the side, the terminal point will be the midpoint of the opposite side, and the displacement = 10 m. If he begins from the corner, the final point is the opposite corner, therefore, the displacement = 10•sqrt2 =14.1 m.

Answer 2

yes

Answer 3

Cheta