Asked by gordana
The farmer wants to use the 500 m to an enclosure divided into two equal areas, What is the total maximum area that can is achieved with the 500 m fence. using differential calculus to the solution.
Answers
Answered by
Bosnian
Enclosure is divide into two equal parts.
Thats why you hawe width 3 times.
Two times of end of fence and one time in midle.
You hawe length 2 times both times of end of fence.
So:
3 W + 2 L = 500
3 W = 500 - 2 L = 2 ( 250 - L )
3 W = 2 ( 250 - L ) Divide both sides by 3
W = ( 2 / 3 ) ( 250 - L )
A = W * L
A = ( 2 / 3 ) ( 250 - L ) * L
A = ( 2 / 3 ) ( 250 L - L ^ 2 )
dA / dL = 250 - 2 L = o
250 - 2 L = 0
250 = 2 L Divide both sides by 2
125 = L
L = 125 m
W = ( 2 / 3 ) ( 250 - L )
W = ( 2 / 3 ) ( 250 - 125 )
W = ( 2 / 3 ) * 125
W = 250 / 3 m
A = W * L
A = 125 * 250 / 3 = 31250 / 3 =
10416.66667 m ^ 2
P.S.
Izvini zbog mog lošeg engleskog.
Thats why you hawe width 3 times.
Two times of end of fence and one time in midle.
You hawe length 2 times both times of end of fence.
So:
3 W + 2 L = 500
3 W = 500 - 2 L = 2 ( 250 - L )
3 W = 2 ( 250 - L ) Divide both sides by 3
W = ( 2 / 3 ) ( 250 - L )
A = W * L
A = ( 2 / 3 ) ( 250 - L ) * L
A = ( 2 / 3 ) ( 250 L - L ^ 2 )
dA / dL = 250 - 2 L = o
250 - 2 L = 0
250 = 2 L Divide both sides by 2
125 = L
L = 125 m
W = ( 2 / 3 ) ( 250 - L )
W = ( 2 / 3 ) ( 250 - 125 )
W = ( 2 / 3 ) * 125
W = 250 / 3 m
A = W * L
A = 125 * 250 / 3 = 31250 / 3 =
10416.66667 m ^ 2
P.S.
Izvini zbog mog lošeg engleskog.
Answered by
gordana
hvala ti puuuuuuuno, I tvoj engleski je suoper
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