Question
Codeine is added to 100ml of water until the solution concentration is 0.800M. What is the pH of this solution?
Answers
DrBob222
What are you using for pKb?
Call codeine BN. Then (BN) = 0.800M
...........BN + HOH ==> BNH^+ + OH
initial...0.800.........0.........0
change.....-x...........x.........x
equil....0.800-x........x.........x
Kb = ? = (BNH^+)(OH^-)/(BN)
Substitute from the ICE chart into the Kb expression and solve for x = OH^-, then convert to pH.
Call codeine BN. Then (BN) = 0.800M
...........BN + HOH ==> BNH^+ + OH
initial...0.800.........0.........0
change.....-x...........x.........x
equil....0.800-x........x.........x
Kb = ? = (BNH^+)(OH^-)/(BN)
Substitute from the ICE chart into the Kb expression and solve for x = OH^-, then convert to pH.