When 100ml of Hg(NO3)2 (aq) fully reacted with Na2S (s), 1g of HgS was producted. In this situation, how much is the molarity of Hg(NO3)??
4 answers
Well I mean, the molarity of Hg(NO3)2. Not Hg(NO3)
1 g of HgS is how many mols of HgS
HgS is 233 g/mol (Hg = 201+ S= 32)
so we have 1/233 mol of HgS
That required 1/233 mol of Hg(NO3)2
(1/233)mol / 0.1 liter = 10/233 mol/liter = .043 M
HgS is 233 g/mol (Hg = 201+ S= 32)
so we have 1/233 mol of HgS
That required 1/233 mol of Hg(NO3)2
(1/233)mol / 0.1 liter = 10/233 mol/liter = .043 M
Thanks a lot
You are welcome.