0.50 ppm means 0.50 mg Cl2/L
So for 134.0 L you need .....?
What mass of chlorine must be added to 134.0 L of water to achieve this level?
anwser grams
So for 134.0 L you need .....?
Mass = Concentration ร Volume
First, let's convert the concentration from parts per million (ppm) to grams per liter (g/L):
1 ppm = 1 mg/L = 0.001 g/L
So, 0.50 ppm = 0.50 ร 0.001 g/L = 0.0005 g/L
Now, we can calculate the mass of chlorine:
Mass = 0.0005 g/L ร 134.0 L
Mass = 0.067 g
Therefore, approximately 0.067 grams of chlorine must be added to 134.0 L of water to achieve a concentration of 0.50 ppm.
First, we need to convert the volume of water from liters to milliliters since the concentration of chlorine is given in parts per million (ppm), which is equivalent to milligrams per liter (mg/L).
1 L = 1000 mL
So, 134.0 L of water is equal to 134.0 ร 1000 mL = 134,000 mL
Next, we can calculate the mass of chlorine using the concentration in ppm.
0.50 ppm means 0.50 mg of chlorine per liter (mg/L).
Since we have 134,000 mL of water, we can set up a proportion to find the mass of chlorine:
(0.50 mg / 1 L) = (x mg / 134,000 mL)
To solve for x, we can cross-multiply and divide:
x mg = (0.50 mg / 1 L) * 134,000 mL
x mg = 67,000 mg
Finally, we need to convert milligrams to grams:
1 g = 1000 mg
67,000 mg is equal to 67,000 รท 1000 = 67 g
Therefore, the mass of chlorine that must be added to 134.0 L of water to achieve a level of 0.50 ppm is 67 grams.