Question
A block of mass'm'is dropped over a horizontal surface with an initial velocity'v'.the coefficient of kinatic friction is'u'(mev),while the acceleration due to gravity'g'before coming to rest the block travels a distance??how i can find the distance?please help me to do so!
Answers
Elena
KE = W(fr)
m•v^2/2 = k•m•g•s,
s = m•v^2/2• k•m•g = v^2/2• k•g
m•v^2/2 = k•m•g•s,
s = m•v^2/2• k•m•g = v^2/2• k•g