M = 4.5 kg
h = 1500cm = 15 m.
F = 1861N/m * 0.12m = 223.32 N.
a = F/m = 223.32/4.5 = 49.63 m/s^2
V2^2 = V1^2 + 2a*h=0 + 99.25*15=1488.8
V2 = 38.6 m/s = Speed of block.
A 4.5 kg block is dropped onto a spring of spring constant 1861 N/m from a height of 1500 cm find the speed of the block when the compression of the spring is 12 cm. The acceleration of gravity is 9.81 m/s
1 answer