Asked by visoth
a car traveling at 30 m/s loses a tire. the tire rolls to a hill which it begins climbing without slipping how high up the hill will the tire climb?
Answers
Answered by
Damon
Kinetic energy at bottom = potential energy at top
Answered by
Damon
(1/2) m v^2 + (1/2)I w^2 = m g h
but w = v/r
(1/2) m v^2 + (1/2)I v^2/r^2 = m g h
v^2 (m + I/r^2) = 2 m g h
You must know something about radius and moment of inertia to get answer.
but w = v/r
(1/2) m v^2 + (1/2)I v^2/r^2 = m g h
v^2 (m + I/r^2) = 2 m g h
You must know something about radius and moment of inertia to get answer.
Answered by
visoth
omg thank you i forgot about kinetic energy and potential energy
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