Asked by Anonymous
A spinning flywheel has a rotational inertia I=400.0 kg metre squared.Its angular velocitydecreases from 20.0rad/secondsto zero in 300.0 seconds due to friction.What is the frictional torque acting?
Answers
Answered by
bobpursley
goodness. See other post
Answered by
visoth
torque = I(moment of inertia) times angular acceleration(change in angular velocity over time) change in angular velocity over time simply put is velocity final - velocity intial divided by total time that's all im doing for you,you should get it form that
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