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Factor using the AC method..6x^3-4x^2-10x
1 answer
first factor out an x.
2x(3x^2-2x-5)
Now you have a quadratic in the form of
(ax^2+bx+c)
2x(3x-5)(x+1)
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It is not solvable by that method, shanaid. You have to get all the numbers on the left, set them to equal zero, and factor.
whic
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