Asked by John
I have this mechanics problem. Please help me solve it.
Rory, Aurora and Raoul are three lions fi ghting over a piece of meat of mass 12
kg.
Each lion exerts a horizontal pull. Rory pulls with a force of 800 N.
Aurora, who is 120degrees to Rory's right, exerts a force of 400 N.
Raoul is 140 degrees to Rory's left.
The meat accelerates in Rory's direction.
(a) Find the force which Raoul is exerting.
Thank you in advance.
Rory, Aurora and Raoul are three lions fi ghting over a piece of meat of mass 12
kg.
Each lion exerts a horizontal pull. Rory pulls with a force of 800 N.
Aurora, who is 120degrees to Rory's right, exerts a force of 400 N.
Raoul is 140 degrees to Rory's left.
The meat accelerates in Rory's direction.
(a) Find the force which Raoul is exerting.
Thank you in advance.
Answers
Answered by
Jat
Let F-Raoul be the force exerted by Raoul.
Consider the direction perpendicular to Rory's direction,
There is no nett force in that direction as there is no movement along it.
F-Raoul Cos(40º) = 400 N * Cos(60º) ------> F-Raoul = 261 N
Nett force in Rory's direction = 800 N - 261 N * Sin(40º) - 400 N * Sin(60º).
You just apply F = m*a to find the acceleration.
Consider the direction perpendicular to Rory's direction,
There is no nett force in that direction as there is no movement along it.
F-Raoul Cos(40º) = 400 N * Cos(60º) ------> F-Raoul = 261 N
Nett force in Rory's direction = 800 N - 261 N * Sin(40º) - 400 N * Sin(60º).
You just apply F = m*a to find the acceleration.
Answered by
smart guy
In the case of resolving the force perpendicular to Rory's direction, isnt it suppose to be F-Raoul cos(50º) = 400 cos(30º) ?
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