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Questions (15)
A particle of mass 5 kg is being towed at a constant speed of 6 m/s on a rough horizontal plane with coefficient of friction
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A block moves on a rough slope of length 10 m inclined at 30 degrees to the horizontal. The coefficiebt of friction between the
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914 views
Q.1 Find the force needed to accelerate a 2 kg block at 3m/s^2 up a rough plane (coefficient of friction 0.2) inclined at 25
4 answers
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A particle of mass m can just rest on a rough plane inclined at 30 degree to the horizontal without slipping down. show that the
1 answer
541 views
A child is splaying with a toy aero plane. the aero plane is flying with velocity (6i + 2j)m/s. A breeze begin to blow with
1 answer
1,297 views
A particle is travelling with velocity (4i+5j)m/s. It undergoes an acceleration of magnitude 2.5m/s^2 in a direction given by
1 answer
1,189 views
A particle p is initially at the point (2, 6) in relation to an origin O, and is moving with velocity (3i + j) m/s. It has a
2 answers
1,033 views
An aircraft is traveling horizontally in an easterly direction at a height of 400 m above level ground and at a speed of 120
1 answer
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An object is moving in a plane. At time t =0,it is at origin O, and moving with velocity u. After 2 seconds, it is at A, where
1 answer
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A boat which can travel at 5m/s in still water is crossing a river 200 m wide.the rate of the flow of the river is 2 m/s assumed
1 answer
1,330 views
When Studying Vectors, How Would I Go About Answering This Question?
In Each of the following Cases, find the magnitude and
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726 views
Starting simultaneously from the same spot, O, Alvin and Bernard set out across a field in the gog. Alvin travels with velocity
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656 views
Triangle ABC with D, E and F the midpoints of BC, AC, and AB. G is the midpoint of AD such that the ratio AG:GD =2:1, VECtors AB
1 answer
632 views
Triangle ABC with D, E and F the midpoints of BC, AC, and AB. G is the midpoint of AD such that the ratio AG:GD =2:1, VECtors AB
0 answers
624 views
A ship is being steered due east. A current is flowing from north to south, so that the actual velocity of the ship is 12 km/h
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794 views
Answers (5)
thanks a lot Elena, your help is much appreciated
First force is F which is pushing block upward Second is the opposing forces, opposite to F The block accelerates, so there is a net force (UNbalanced forces) which is net F =(F-opposing forces). Since they are unbalanced and acceleration A results: netF =
Let F-Raoul be the force exerted by Raoul. Consider the direction perpendicular to Rory's direction, There is no nett force in that direction as there is no movement along it. F-Raoul Cos(40º) = 400 N * Cos(60º) ------> F-Raoul = 261 N Nett force in
a)by Phythagorous c^2 =a^2 + b^2 = 5^2+ 2^2=25+4=29 c=5.38m/s b)sin (theta)=2/5 theta = sin^-1 (2/5) theta=23.57 degree
In the direction of x u = 4i, a= 2.5(3/5) At t =4 v = u+at v= 4 + 2.5 (3/5)4=4+6=10 In the direction of y u = 5j, a= 2.5(-4/5) At t =4 v = u+at v= 5 + 2.5 (-4/5)4=5-8=-3 Hence V = 10i-3j Now we have initial and final velocities r = 1/2(u +v)t r =