Asked by Alex
Find the length of a simple pendulum that completes 17.0 oscillations in 35.0 s.
Answers
Answered by
Elena
The period is T = t/N = 35/17 = 2.06 s.
T =2•π•sqrt(L/g),
L= T^2•g/(2• π)^2
T =2•π•sqrt(L/g),
L= T^2•g/(2• π)^2
Answered by
Jim Herald
.056 cm
Answered by
gerwin garsain
puta ka
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.