Asked by Alex
Find the length of a simple pendulum that completes 17.0 oscillations in 35.0 s.
Answers
Answered by
Elena
The period is T = t/N = 35/17 = 2.06 s.
T =2•π•sqrt(L/g),
L= T^2•g/(2• π)^2
T =2•π•sqrt(L/g),
L= T^2•g/(2• π)^2
Answered by
Jim Herald
.056 cm
Answered by
gerwin garsain
puta ka