Asked by Elisa
A simple pendulum with a length of 1.50 m is suspended from the ceiling of a train. What is the period of simple harmonic motion for the pendulum if the train is moving up an incline of 15.0˚ with an acceleration of 3.00 m/s²?
Don't know how to do, please help
Don't know how to do, please help
Answers
Answered by
drwls
The pendulum will act as if the gravitational acceleration were the vector sum of g (down) and -a, aimed 15 degrees below horizontal. Call the resultant g'
g' = sqrt (g^2 + a^2 - 2 ag cos 105) = 10.96 m/s^2
Then use g' instead of g in the formula for the period.
P = 2 pi sqrt (L/g')
Just adding the vertical component of a to g will not get you the right answer for g'.
g' = sqrt (g^2 + a^2 - 2 ag cos 105) = 10.96 m/s^2
Then use g' instead of g in the formula for the period.
P = 2 pi sqrt (L/g')
Just adding the vertical component of a to g will not get you the right answer for g'.
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