The sum of the heats gained is zero.
heatgainedbyIron+heatgainedbyWater=0
.43*specheatiron*(36-Ti)+1.60*specheatwater*(26-20)=0
solve for Ti
A hot iron horseshoe (mass = 0.43 kg), just forged (Fig. 14-16), is dropped into 1.60 L of water in a 0.26 kg iron pot initially at 20°C. If the final equilibrium temperature is 26°C, estimate the initial temperature of the hot horseshoe.
Could someone please help me out with how to do this. Thank you!
2 answers
T is final iron temp
a liter of water is a kilogram
heat out of horseshoe = heat into water + heat into pot
.43 Ciron (T-26) = 1.6 Cwater (6 ) + .26 Ciron(6)
a liter of water is a kilogram
heat out of horseshoe = heat into water + heat into pot
.43 Ciron (T-26) = 1.6 Cwater (6 ) + .26 Ciron(6)
1 answer