An athlete executing a long jump leaves the ground at a 28.0 angle and lands 7.60m away.

Question

part a)What was the takeoff speed?

part b) If this speed were increased by just 8.0 % , how much longer would the jump be?

i got for part a)9.48 m/s
but i need help with part b

Answer 1

L = v^2•sin2α/g ,
v = sqrt(L•g/sin2α) = 9.48 m/s.
New velocity
V =1.08•v = 1.08•9.48= 10.24 m/sþ
New range is L1 = V^2•sin2α/g = 8.87 m.
ΔL = 8.87 – 7.6 = 1.27 m