A parallel plate capacitor has area of 2cm^2 and a plate separation of 1mm. Find capacitance.

Answer 1

C=ErEoA/d where C is the capacitance, A is the area overlap of the two plates Er is the relative static permitivity9sometimes called dielectric constant of the material between the plates(for a vacuum,Er=1)Eo is dielectric constant(Eo=8.854x10^-12Fm-1 and d is the separation distance between the plates.C=(1X8.854X10^-12X2)/1