Asked by Tor
A parallel-plate capacitor has a capacitance of 2.1 µF with air between the plates. The capacitor is connected to a 24 V battery and charged. The battery is then removed. When a dielectric is placed between the plates, a potential difference of 2.8 V is measured across the plates. What is the dielectric constant of the material?
Answers
Answered by
Brian
In an isolated instance the voltage goes down by a factor of K.
24 v / k = 2.8 v
k = 8.6 (rounded to sig figs)
24 v / k = 2.8 v
k = 8.6 (rounded to sig figs)
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