Asked by Jane
The length of an open-top box is 4 cm longer than its width. The box was made from a 480-cm^2 rectangular sheet of material with 6cm by 6cm squares cut from each corner. The height of the box is 6cm. Find the dimensions of the box.
Please show me in detail how to set this up and solve.
Please show me in detail how to set this up and solve.
Answers
Answered by
Damon
area of sides = 2 L *6 + 2 W*6
= 12 L + 12 W
area of bottom = L W
total area = L W + 12 L + 12 W = 480-4*36
so
L W + 12 L + 12 W = 336
but L = W + 4
(W+4)W + 12(W+4) + 12 W - 336 = 0
W^2 + 28 W -288 = 0
(W -16)(W+18) = 0
W = 16
L = 16+4 = 20
= 12 L + 12 W
area of bottom = L W
total area = L W + 12 L + 12 W = 480-4*36
so
L W + 12 L + 12 W = 336
but L = W + 4
(W+4)W + 12(W+4) + 12 W - 336 = 0
W^2 + 28 W -288 = 0
(W -16)(W+18) = 0
W = 16
L = 16+4 = 20
Answered by
lololol
l=4+w
w=l-4
h=6
v=480
v=lwh
480=12 x 8 x 6
w=l-4
h=6
v=480
v=lwh
480=12 x 8 x 6
Answered by
lololol
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