Asked by vero

The length of a rectangular picture is seven iches longer than the width. Find the length and the width if the perimeter of the picture is 62 inches.
2L+2w=62
2L+2w+7=62
4L+7 =62
4L=7+62
4L=69
4L=69/4

2L+2w=62 <b>You are ok to here.
length is 7" longer than the width; therefore, L = w+7, so
2(w+7)+ 2w = 62</b>

2L+2w+7=62
4L+7 =62
4L=7+62
4L=69
4L=69/4

I don' t understand the rest of the problem would it be
2L+2w=62
L =w+7
2(w+&0+2=62
2w+7+2=62
11w=62
w=11+62
w=78

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