Asked by Anonymous
8. When a person stands on a rotating merry go round, the frictional force exerted on the person by the merry go round is
(A) greater in magnitude than the frictional force exerted on the person by the merry go round
(B) opposite in direction to the frictional force exerted on the merry go round by the person
(C) directed away from the center of the merry go round
(D) zero if the rate of rotation is constant
(E) independent of the person's mass
I have that the answer is b, but why isn't it E?
(A) greater in magnitude than the frictional force exerted on the person by the merry go round
(B) opposite in direction to the frictional force exerted on the merry go round by the person
(C) directed away from the center of the merry go round
(D) zero if the rate of rotation is constant
(E) independent of the person's mass
I have that the answer is b, but why isn't it E?
Answers
Answered by
Brad
two narrow slits 0.12 mm apart. Light of wavelength 550n illuminates the slits, causeing an interference pattern on a screen 1.0 m away. Light from each slit travels to the m = 1 maximum on the right side of the central maximum. How much farther did the light from the left slit travel then the light from the right slit? ....
where do i begin and how do i get the answer
where do i begin and how do i get the answer
Answered by
dave
Brad, you might be dead now because you posted in2008, but it isn't independent of mass because the force of friction is the coefficient of static friction times normal force, and normal force=MASS*g.
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