Question
Radioactive radium () has a half-life of 1599 years. What percent of a given amount will remain after years?
Answers
Pamela
radio active radium(226)
Steve
Let P be the initial amount
n be the years
A the amount remaining after n years
A = P*(1/2)^(n/1599)
A/P = (1/2)^(n/1599)
so, the % remaining is
100*(1/2)^(n/1599)
n be the years
A the amount remaining after n years
A = P*(1/2)^(n/1599)
A/P = (1/2)^(n/1599)
so, the % remaining is
100*(1/2)^(n/1599)