Asked by josh
A closed container has a mixture of methane, CH4, ethane C2H6, and propane C3H8. If 12.5 g of methane, 36.0 g of ethane, and 14.0 g of propane have a total pressure of 890. mm Hg, what is the partial pressure of each of the gases in the container?
Answers
Answered by
DrBob222
Convert grams each gas to mols.
mols = g/molar mass
Convert each gas to mole fraction.
Xeach gas = mol each gas/total mols.
partial pressure each gas = Xeach gas*Ptotal
mols = g/molar mass
Convert each gas to mole fraction.
Xeach gas = mol each gas/total mols.
partial pressure each gas = Xeach gas*Ptotal
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