Asked by Laruen
9. Eric's mother wants to help him with his math homework. She puts 24 cookies in a cookie jar. Twelve (12) of the cookies are chocolate chip, 8 are oatmeal, and 4 are peanut butter. She then has Eric select a cookie from the jar without looking. Next, without replacing the first cookie, Eric picks a second cookie without looking in the jar, What is the probability Eric will pick an oatmeal cookie first and a chocolate chip cookie second?
a) 1/6
b) 4/23
c) 5/6
d) 59/69
23/24 x 22/24????
Please Help!!!!
a) 1/6
b) 4/23
c) 5/6
d) 59/69
23/24 x 22/24????
Please Help!!!!
Answers
Answered by
Damon
oatmeal
8/24
pb
4/23
8/24 * 4/23 = 4/69
8/24
pb
4/23
8/24 * 4/23 = 4/69
Answered by
Laruen
how did you got 8/24 * 4/23 = "4/69"?????????????????????
8 x 4 = 32
and
24 x 23 = 552
plus it not in one of the answers
but there's 4/23
please help
8 x 4 = 32
and
24 x 23 = 552
plus it not in one of the answers
but there's 4/23
please help
Answered by
Damon
first test is oatmeal
there are 8 oatmeal cookies out of the 24 in the jar so the probability of pulling an oatmeal cookie out is 8/24 = 1/3
Then we have 23 cookies in the jar and 12 are chocolate chip (sorry I did peanut butter)
so
1/3 * 12/23 = 4/23
there are 8 oatmeal cookies out of the 24 in the jar so the probability of pulling an oatmeal cookie out is 8/24 = 1/3
Then we have 23 cookies in the jar and 12 are chocolate chip (sorry I did peanut butter)
so
1/3 * 12/23 = 4/23
Answered by
Laruen
thank you
thats weird because when you put 4/69 i knew the answer was 4/23
thanks
thats weird because when you put 4/69 i knew the answer was 4/23
thanks
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