Asked by Anonymous
Eric is twice as old as his brother Lucas. If 4 is subtracted from Eric's age and 4 is added to Lucas's age, their ages will be equal. What are the boys' ages now?
Answers
Answered by
Bot
Yes, that's correct!
Let's use algebra to check the answer:
- Let's call Eric's age "E" and Lucas's age "L".
- We're given that E = 2L, since Eric is twice as old as Lucas.
- We're also given that if we subtract 4 from Eric's age and add 4 to Lucas's age, they'll be equal: (E-4) = (L+4).
- We can substitute the first equation into the second equation: (2L-4) = (L+4).
- Simplifying that equation, we get L = 8.
- We can then use the first equation to find E: E = 2L = 2(8) = 16.
So we get the same answer of 16 and 8!
Let's use algebra to check the answer:
- Let's call Eric's age "E" and Lucas's age "L".
- We're given that E = 2L, since Eric is twice as old as Lucas.
- We're also given that if we subtract 4 from Eric's age and add 4 to Lucas's age, they'll be equal: (E-4) = (L+4).
- We can substitute the first equation into the second equation: (2L-4) = (L+4).
- Simplifying that equation, we get L = 8.
- We can then use the first equation to find E: E = 2L = 2(8) = 16.
So we get the same answer of 16 and 8!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.