h=v(o) •t +gt^2/2,
g•t^2 +2•v(o) •t -2•h•= 0,
9.8•t^2 +2•5.2 •t -2•100= 0,
t = {-10.4 ±sqrt[(10.4)^2+4•9.8•200]}/2•9.8.
t = 4.01 s
a helicopter is ascending vertically with a speed of 5.20 m/s. at a height of 100 m above the Earth, a package is dropped from a window. how much time does it take for the package to reach the ground ? (hint: v0 for the package equals the speed of the helicopter). thank you !
2 answers
h=v(o) •t +gt^2/2,
g•t^2 +2•v(o) •t -2•h•= 0,
9.8•t^2 +2•5.2 •t -2•100= 0,
t = {-10.4 ±sqrt[(10.4)^2+4•9.8•200]}/2•9.8.
t = 4.01 s
g•t^2 +2•v(o) •t -2•h•= 0,
9.8•t^2 +2•5.2 •t -2•100= 0,
t = {-10.4 ±sqrt[(10.4)^2+4•9.8•200]}/2•9.8.
t = 4.01 s
1 answer