Question

a helicopter is ascending vertically with a speed of 5.20 m/s with package of negligible size attached to the bottom of the helicopter, when the helicopter is 125 m above the ground the package is released and the helicopter continues to ascend at its same speed. air resistance is negligible in this problem.(a)what is the displacement of the helicopter 5 seconds after the package has been released?(b)what is the displacement of the package 5.0 seconds after it has been released?(c)how far apart are the bottom of the helicopter and the package after 5.0 seconds?

Answer 1

a. displacement= 125+5.20*5 above ground
b. s=125+5.2*5+ 1/2 g t^2 (t=5, g is =9.8m/s^2)

c. subtract.

Answer 2

(a) 125 m + (5.20 m/s * 5 s)

(b) [-4.9 m/s^2 * (5 s)^2] + (5.20 m/s * 5 s) + 125 m

(c) result (a) - result (b)