Question
A bacterial population starts at 500 and doubles every four days. Find a formula for the population after t days and find the percentage rate of change in population.
Answers
bobpursley
population= Original*(2^(t/5))
rate of change
dpopulation/dt= t/5 * ln2* 2^(t/5) * original
for percentate, then percent= 100*dpopulation/dt / original= 100*t/5*ln2*2^t/5
rate of change
dpopulation/dt= t/5 * ln2* 2^(t/5) * original
for percentate, then percent= 100*dpopulation/dt / original= 100*t/5*ln2*2^t/5