Asked by Sandra Gibson
A bacterial population starts at 500 and doubles every four days. Find a formula for the population after t days and find the percentage rate of change in population.
Answers
Answered by
bobpursley
population= Original*(2^(t/5))
rate of change
dpopulation/dt= t/5 * ln2* 2^(t/5) * original
for percentate, then percent= 100*dpopulation/dt / original= 100*t/5*ln2*2^t/5
rate of change
dpopulation/dt= t/5 * ln2* 2^(t/5) * original
for percentate, then percent= 100*dpopulation/dt / original= 100*t/5*ln2*2^t/5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.