Question
2. A pool has an area A = 50 m2 and depth h = 2.5 m. The pool is filled with water to the maximum height. An electrical pump is used to empty the pool. There are two pipes coming out the pump: one is submerged into water has a radius r1 = 4 cm the other has a radius r2 = 2.5 cm. Answer the following questions ignoring friction, viscosity, turbulence.
Calculate the net force on the bottom of the pool.
Calculate work done by the pump required to empty the pool in 5 h.
Calculate the speed of the water flow in the submerged pipe.
Calculate the net force on the bottom of the pool.
Calculate work done by the pump required to empty the pool in 5 h.
Calculate the speed of the water flow in the submerged pipe.
Answers
Henry
a. V=A*h = 50*2.5=125 m^3=1.25*10^8 cm^3.
Dw = 1g/cm^3 = 0.001kg/cm^3 = Density of water.
Mass=1.25*10^8cm^30.001kg/cm^3
= 1.25*10^5 kg = Mass of the water.
F=mg = 1.25*10^5kg * 9.8N/kg = 1.225*10^6 N. = Force on bottom.
b. Work = F*d = 1.225*10^6 * 2.5 = =
3.0625*10^6 Joules.
Dw = 1g/cm^3 = 0.001kg/cm^3 = Density of water.
Mass=1.25*10^8cm^30.001kg/cm^3
= 1.25*10^5 kg = Mass of the water.
F=mg = 1.25*10^5kg * 9.8N/kg = 1.225*10^6 N. = Force on bottom.
b. Work = F*d = 1.225*10^6 * 2.5 = =
3.0625*10^6 Joules.
John
a.)
P=P initial + pgh
101,000 Pa + (1000)(9.8)(2.5)
P=125500Pa.
P=F/A
125500=F/50
6.3*10^6N
P=P initial + pgh
101,000 Pa + (1000)(9.8)(2.5)
P=125500Pa.
P=F/A
125500=F/50
6.3*10^6N