Asked by Mhd
find the slope of the tangent line at the point (1,2) for the ellipse 2x^2+3y^2=14
y'(1) = ??
y'(1) = ??
Answers
Answered by
Reiny
differentiate implicitly
4x + 6y dy/dx = 0
dy/dx = -6y/(4x) = -3y/(2x)
sub in (1,2) to get the slope
take it from there
4x + 6y dy/dx = 0
dy/dx = -6y/(4x) = -3y/(2x)
sub in (1,2) to get the slope
take it from there
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