Asked by Ana
Find the slope of the tangent to the curve y^2=x^3/(xy+6) at (6,3)
Answers
Answered by
bobpursley
y^2(xy+6)=x^3
2yy'(xy+6)+y^2xy'=3x^2
y'(2y(xy+6)+y^2x)=3x^2
solve for y' at 6,3
2yy'(xy+6)+y^2xy'=3x^2
y'(2y(xy+6)+y^2x)=3x^2
solve for y' at 6,3
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