Asked by Beth
Describe how you would prepare 2.00 L of an aqueous solution having a pH=3.60, if you had a supply of 0.100 M HCl available.
Answers
Answered by
DrBob222
Convert pH to H^+.
pH = -log(H^+), then
c1v1 = c2v2
c = concn
v = volume
pH = -log(H^+), then
c1v1 = c2v2
c = concn
v = volume
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