Asked by Anonymous
describe how you would prepare 500ml of a solution containing 0.025M sodium acetate and 0.001% w/v starch.
Answers
Answered by
DrBob222
0.025M NaAc:
How many mols do you need? That M x L = mols. Then mol = grams/molar mass. You know molar mass and mols solve for grams.
0.001% w/v starch.
0.001g (1 mg) starch in 100 mL solution.
How many mols do you need? That M x L = mols. Then mol = grams/molar mass. You know molar mass and mols solve for grams.
0.001% w/v starch.
0.001g (1 mg) starch in 100 mL solution.
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