Asked by Anonymous
Suppose T varies directly as the 3/2 power of x. When x=16, T=160. Find T when x=4
Answers
Answered by
Steve
T = kx^3/2
160 = k*16^3/2 = k*4^3 = 64k
k = 5/2
T = 5/2 x^3/2
T(4) = 5/2 * 4^3/2 = 5/2 * 2^3 = 20
160 = k*16^3/2 = k*4^3 = 64k
k = 5/2
T = 5/2 x^3/2
T(4) = 5/2 * 4^3/2 = 5/2 * 2^3 = 20
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